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Proof step 7 from proof maxinf-skolemf (previous step)

np(n1), np(n0), n1 < m, np(m), ∀ n0. n1 < n0 → ¬ np(n0) ⊦ m = 0, ∃ n0. n < n0 ∧ np(n0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: m

Additional information

Used terms: m