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Proof step 5 from proof min-zero (previous step)

mon<(nσ), ⌜min(nσ, 0)⌝ < # nσ, ∀ m. ⌜m⌝ < # nσ → min(nσ, 0) ≤ m ⊦ min(nσ, 0) = 0, nσ = []

User applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: 0 abort: F discard: T computed: F

Additional information

Used simplifier rules: zero-len: ⊦ ⌜0⌝ < # nσ ↔ nσ ≠ []; from specification stream[natstream]%lez-01: ⊦ m ≤ 0 ↔ m = 0; from specification nat Used terms: 0