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Proof step 21 from proof mininv-stays-if-not-taken (previous step)

n = nσ[min(nσ, n)], n < nσ[min(nσ, n + 1)], min(nσ, n) < min(nσ, n + 1), mon<(nσ), ⌜min(nσ, n + 1)⌝ < # nσ, ⌜min(nσ, n)⌝ < # nσ, # nσ = ∞ ∨ n < nσ[(# nσ).n - 1], ∀ m. ⌜m⌝ < # nσ ∧ n ≤ nσ[m] → min(nσ, n) ≤ m, # nσ = ∞ ∨ ¬ nσ[(# nσ).n - 1] < n, ∀ m. ⌜m⌝ < # nσ → nσ[m] ≠ n, ∀ m. ⌜m⌝ < # nσ ∧ n < nσ[m] → min(nσ, n + 1) ≤ m ⊦ min(nσ, n + 1) = 0, nσ[min(nσ, n + 1)] = 0, nσ = [], min(nσ, n + 1) = min(nσ, n)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 10 terms: min(nσ, n)

Additional information

Used terms: min(nσ, n)