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Proof step 8 from proof monls-append1 (previous step)

nl[n + 1] ≤ nl[n], 1 + n < # nl, ∀ n0. 1 + n0 < # nl0 + # nl → (nl + nl0)[n0] < (nl + nl0)[n0 + 1] ⊦ nl = []

User applied rule all left

And obtained the following new goals

Proof step 9:
nl[n + 1] ≤ nl[n], 1 + n < # nl, 1 + n < # nl0 + # nl → (nl + nl0)[n] < (nl + nl0)[n + 1] ⊦ nl = []

Rule argument

pos: left 3 terms: n abort: F discard: T computed: F

Additional information

Used terms: n