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Proof step 12 from proof monls-exists-maxleq (
previous step
)
mon<(nσ), nσ[0] ≤ n, n < nσ[m], ⌜m⌝ < # nσ ⊦ ∃ m0. nσ[m0] ≤ n ∧ n < nσ[m0 + 1] ∧ m0 ≤ m
Lemma
monls-exists-maxls