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Proof step 14 from proof monls-exists-maxleq (previous step)

nσ[0] < nσ[m0 + 1], nσ[m0] < nσ[m], nσ[m0] < nσ[m0 + 1], nσ[0] + 1 < nσ[m], nσ[0] < n, mon<(nσ), nσ[0] < nσ[m], ⌜m⌝ < # nσ, n < nσ[m], m0 ≤ m, n < nσ[m0 + 1], nσ[m0] ≤ n, nσ[0] + 1 < nσ[m0 + 1] ⊦ nσ[m0 + 1] = 0, n = nσ[m], n = 0, nσ[m] = 0, ∃ m0. nσ[m0] < n ∧ n ≤ nσ[m0 + 1] ∧ m0 ≤ m

User applied rule exists right

And obtained the following new goals

Proof step 15:
nσ[0] < nσ[m0 + 1], nσ[m0] < nσ[m], nσ[m0] < nσ[m0 + 1], nσ[0] + 1 < nσ[m], nσ[0] < n, mon<(nσ), nσ[0] < nσ[m], ⌜m⌝ < # nσ, n < nσ[m], m0 ≤ m, n < nσ[m0 + 1], nσ[m0] ≤ n, nσ[0] + 1 < nσ[m0 + 1] ⊦ nσ[m0 + 1] = 0, n = nσ[m], n = 0, nσ[m] = 0, nσ[m0] < n ∧ n ≤ nσ[m0 + 1] ∧ m0 ≤ m, ∃ m0. nσ[m0] < n ∧ n ≤ nσ[m0 + 1] ∧ m0 ≤ m

Rule argument

pos: right 5 terms: m0 abort: F discard: F computed: F

Additional information

Used terms: m0