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Proof step 4 from proof monls-exists-maxleq (previous step)

⌜m⌝ < # nσ, nσ[0] < nσ[m], mon<(nσ) ⊦ nσ[m] = 0, ∃ m0. nσ[m0] < nσ[m] ∧ nσ[m] ≤ nσ[m0 + 1] ∧ m0 ≤ m

User applied rule constructor cut

And obtained the following new goals

Proof step 5:
m = m1 +1, ⌜m⌝ < # nσ, nσ[0] < nσ[m], mon<(nσ) ⊦ nσ[m] = 0, ∃ m0. nσ[m0] < nσ[m] ∧ nσ[m] ≤ nσ[m0 + 1] ∧ m0 ≤ m

Rule argument

var: m

Additional information

Used simplifier rules: nat freely generated by 0, +1;;%zero-len: ⊦ ⌜0⌝ < # nσ ↔ nσ ≠ []; from specification stream[natstream]%ref-1: ⊦ ¬ n < n; from specification nat-basic1