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Proof step 6 from proof monls-exists-maxleq (previous step)

mon<(nσ), ⌜m1⌝ + ⌜1⌝ < # nσ, nσ[0] < nσ[m1 + 1] ⊦ nσ[m1 + 1] = 0, ∃ m. nσ[m] < nσ[m1 + 1] ∧ nσ[m1 + 1] ≤ nσ[m + 1] ∧ m ≤ m1 + 1

User applied rule exists right

And obtained the following new goals

Proof step 7:
mon<(nσ), ⌜m1⌝ + ⌜1⌝ < # nσ, nσ[0] < nσ[m1 + 1] ⊦ nσ[m1 + 1] = 0, nσ[m1] < nσ[m1 + 1] ∧ nσ[m1 + 1] ≤ nσ[m1 + 1] ∧ m1 ≤ m1 + 1

Rule argument

pos: right 2 terms: m1 abort: F discard: T computed: F

Additional information

Used terms: m1