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Proof step 7 from proof monls-notsmall (previous step)

nσ[0] = 0, mon<(nσ), ⌜2⌝ + ⌜n0⌝ < # nσ, nσ[2 + n0] ≤ n0 + 1, ∀ nσ0. mon<(nσ0) ∧ nσ0[0] = 0 ∧ ⌜n0⌝ + ⌜1⌝ < # nσ0 → n0 < nσ0[n0 + 1] ⊦

User applied rule all left

And obtained the following new goals

Proof step 8:
nσ[0] = 0, mon<(nσ), ⌜2⌝ + ⌜n0⌝ < # nσ, nσ[2 + n0] ≤ n0 + 1, mon<(nσ) ∧ nσ[0] = 0 ∧ ⌜n0⌝ + ⌜1⌝ < # nσ → n0 < nσ[n0 + 1] ⊦

Rule argument

pos: left 5 terms: nσ abort: F discard: T computed: T

Additional information

Used terms: nσ