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Proof step 1 from proof monlsinf-notsmall (conclusion)

⊦ mon<(⌜nnf⌝ ) ∧ nnf(0) = 0 → (¬ n < nnf(n + 1) ↔ false)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
nnf(0) = 0, mon<(⌜nnf⌝ ), nnf(n + 1) ≤ n ⊦

Rule argument

Additional information

Used simplifier rules: lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat