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Proof step 12 from proof rem-preserves-monls (previous step)

¬ np(# nl0), mon<(⌜nl0⌝ + ⌜m '⌝ ), ∀ nl1, np. # nl1 < #(nl0 + m ') → mon<(⌜nl1⌝ ) → mon<(rem(⌜nl1⌝ , np)) ⊦ mon<(rem(⌜nl0⌝ , np) + ⌜m '⌝ )

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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