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Proof step 23 from proof rem-preserves-monls (previous step)

⊦ ⌜m⌝ < # rem(⌜nl⌝ , np) → (∃ m0. m0 < # nl ∧ nl[m0] = rem(⌜nl⌝ , np)[m] ∧ ¬ np(m0))

A spec-lemma