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Proof step 1 from proof stutf-alltaken (conclusion)

⊦ stutf(nσ) ∧ ⌜m⌝ < # nσ ∧ n ≤ nσ[m] → (∃ m0. m0 ≤ m ∧ nσ[m0] = n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information