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Proof step 12 from proof stutf-maxinf-is-fin (previous step)

# nσ = ∞, m0 ≤ n, nσ[m0] ≤ nσ[n], stutf(nσ), ∀ n1. ∃ n0. n1 < n0 ∧ nσ[n0] = nσ[m0] ⊦ ∃ n. ∀ n0. ¬ n0 < n → nσ[n0] = nσ[m0]

User applied rule exists right

And obtained the following new goals

Proof step 13:
# nσ = ∞, m0 ≤ n, nσ[m0] ≤ nσ[n], stutf(nσ), ∀ n1. ∃ n0. n1 < n0 ∧ nσ[n0] = nσ[m0] ⊦ ∀ n0. ¬ n0 < m0 → nσ[n0] = nσ[m0]

Rule argument

pos: right 1 terms: m0 abort: F discard: T computed: F

Additional information

Used terms: m0