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Proof step 17 from proof stutf-maxinf-is-fin (previous step)

# nσ = ∞, m0 ≤ n0, stutf(nσ), nσ[m0] ≤ nσ[n], m0 ≤ n, nσ[m0] < nσ[n0], ∀ n1. ∃ n0. n1 < n0 ∧ nσ[n0] = nσ[m0] ⊦ nσ[n0] = nσ[m0], nσ[n0] = 0

User applied rule all left

And obtained the following new goals

Proof step 18:
# nσ = ∞, m0 ≤ n0, stutf(nσ), nσ[m0] ≤ nσ[n], m0 ≤ n, nσ[m0] < nσ[n0], ∃ n. n0 < n ∧ nσ[n] = nσ[m0] ⊦ nσ[n0] = nσ[m0], nσ[n0] = 0

Rule argument

pos: left 7 terms: n0 abort: F discard: T computed: F

Additional information

Used terms: n0