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Proof step 25 from proof stutf-maxinf-is-fin (previous step)

# nσ = ⌜n0⌝ , m ≤ nσ[n], stutf(nσ), n < n0, ∀ n. ∃ n0. n < n0 ∧ ⌜n0⌝ < # nσ ∧ nσ[n0] = m ⊦ n0 = 0

User applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: n0 abort: F discard: T computed: F

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%lf: ⊦ m < n ∧ n < n0 → m +1 < n0; (forward) from specification nat-basic1%trans-1: ⊦ n < n0 ∧ n0 < n1 → n < n1; (forward) from specification nat-basic1%succ: ⊦ m +1 = m + 1; from specification nat-basic2%less-fin: ⊦ ⌜m⌝ < ⌜n⌝ ↔ m < n; from specification nat-inf%ls-02: ⊦ m < n → ¬ n < m; from specification nat-basic1 Used terms: n0