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Proof step 31 from proof stutf-maxinf-is-fin (previous step)

stutf(nσ) ∧ ⌜n⌝ < # nσ ∧ m ≤ nσ[n] → (∃ m0. m0 ≤ n ∧ nσ[m0] = m), ⌜n⌝ < # nσ, stutf(nσ), m ≤ nσ[n], ∀ n. ¬ ⌜n⌝ < # nσ ∨ nσ[n] ≠ m, ⌜m⌝ < # nσ ∧ m ≤ nσ[m] → m0 ≤ nσ[m0] ∧ nσ[m0] = m ⊦ # nσ = ∞ ∧ (∃ n. ∀ n0. ¬ n0 < n → nσ[n0] = m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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