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Proof step 40 from proof stutf-maxinf-is-fin (previous step)

# nσ = ∞, nσ[n2] = nσ[n], stutf(nσ), n2 ≤ n0, ∀ n1. ¬ n1 < n2 → nσ[n1] = nσ[n] ⊦ ∃ n1. n0 < n1 ∧ nσ[n1] = nσ[n]

User applied rule exists right

And obtained the following new goals

Proof step 41:
# nσ = ∞, nσ[n2] = nσ[n], stutf(nσ), n2 ≤ n0, ∀ n1. ¬ n1 < n2 → nσ[n1] = nσ[n] ⊦ n0 < n0 +1 ∧ nσ[n0 +1] = nσ[n]

Rule argument

pos: right 1 terms: n0 +1 abort: F discard: T computed: T

Additional information

Used terms: n0 +1