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Proof step 7 from proof stutf-monle (previous step)

⌜n⌝ + ⌜1⌝ < # nσ, nσ ≠ [] ∧ nσ[0] = 0 ∧ (∀ n. ⌜n⌝ + ⌜1⌝ < # nσ → nσ[n + 1] = nσ[n] ∨ nσ[n + 1] = nσ[n] + 1), nσ[n + 1] < nσ[n] ⊦ nσ[n] = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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