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Proof step 4 from proof stutf-slowincrease (previous step)

⌜m⌝ + ⌜n0⌝ + ⌜1⌝ < # nσ, nσ[m] + n0 + 1 < nσ[m + n0 + 1], stutf(nσ), ∀ nσ0, m0. ¬ nσ0[m0] + n0 < nσ0[m0 + n0] ∨ ¬ ⌜m0⌝ + ⌜n0⌝ < # nσ0 ∨ ¬ stutf(nσ0) ⊦

User applied rule all left

And obtained the following new goals

Proof step 5:
⌜m⌝ + ⌜n0⌝ + ⌜1⌝ < # nσ, nσ[m] + n0 + 1 < nσ[m + n0 + 1], stutf(nσ), ¬ nσ[m] + n0 < nσ[m + n0] ∨ ¬ ⌜m⌝ + ⌜n0⌝ < # nσ ∨ ¬ stutf(nσ) ⊦

Rule argument

pos: left 4 terms: nσ, m abort: F discard: T computed: F

Additional information

Used terms: nσ, m