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Proof step 9 from proof app (previous step)

unique_al(ax0 + p0 ' + ay), unique_al(ax0 + p0 ' + ay) → unique_al(ax0 + ay) ⊦ ¬ a ∈ ax0 + ay ∧ unique_al(ax0 + ay), a ∈ ax0 + p0 ' + ay

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: inapp: ⊦ a ∈ ax + ay ↔ ¬ ¬(a ∈ ax ∨ a ∈ ay);% ⊦ (ax + ax0) + ax1 = ax + ax0 + ax1;