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Proof step 12 from proof at-put (previous step)

∀ a, b, d. a = b ∨ ax0[b, d][a] = ax0[a] ⊦ a = b, a = a0, b = a0, ax0[b, d][a] = ax0[a]

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: a, b, d

Additional information

Used terms: a, b, d