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Proof step 8 from proof at-put (previous step)

b ≠ a0, ∀ a, b, d. a = b ∨ ax0[b, d][a] = ax0[a] ⊦ a = b, ((a0 × d0)' + ax0[b, d])[a] = ((a0 × d0)' + ax0)[a]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information