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Proof step 2 from proof inkeys-n (previous step)

a × d ∈ ax ⊦ a = b, ∃ d1. a × d1 = b × d0 ∨ a × d1 ∈ ax

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: d

Additional information

Used terms: d