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Proof step 10 from proof lastoccurrence-key (previous step)

⊦ a ∈ ax1, ∃ ax3, d1, ax2. (a0 × d)' + ax + (a × d0)' + ax1 = ax3 + (a × d1)' + ax2 ∧ ¬ a ∈ ax2

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: (a0 × d)' + ax, d0, ax1

Additional information

Used simplifier rules: ⊦ (ax + ax0) + ax1 = ax + ax0 + ax1; Used terms: (a0 × d)' + ax, d0, ax1