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Proof step 9 from proof lenle (previous step)

# ay ≤ # ax0, unique_al(ax0), a ∈ ax0 ∨ a = a → a ∈ ay, ∀ a0. a0 ∈ ax0 → a0 ∈ ay ⊦ ax0 = [], a ∈ ax0, ∃ ay0. (∀ a. a ∈ ax0 → a ∈ ay0) ∧ ¬ # ax0 ≤ # ay0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
# ay ≤ # ax0, unique_al(ax0), a ∈ ay, ∀ a0. a0 ∈ ax0 → a0 ∈ ay ⊦ ax0 = [], a ∈ ax0, ∃ ay0. (∀ a. a ∈ ax0 → a ∈ ay0) ∧ ¬ # ax0 ≤ # ay0

Proof step 9 from proof lenle (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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