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Proof step 19 from proof perm-unique (previous step)

a × d0 ∈ ay, a × d0 ∈ ay -1l (a × d), unique_al(ay -1l (a × d)), perm(ay -1l (a × d), ax0), unique_al(ax0), perm(ay, (a × d)' + ax0), a × d ∈ ay, perm(ax0, ay -1l (a × d)) ⊦ unique_al(ay), ∃ d. a × d ∈ ax0

User applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: d0 abort: F discard: F computed: F

Additional information

Used simplifier rules: ⊦ p ∈ ax ∧ ¬ p ∈ ax0 → ¬ perm(ax0, ax); Used terms: d0