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Proof step 9 from proof perm-unique (previous step)

perm(ax0, ay -1l (a × d)), a × d ∈ ay, perm(ay, (a × d)' + ax0), unique_al(ax0), perm(ay -1l (a × d), ax0), ∀ ay0. perm(ay0, ax0) ∧ perm(ax0, ay0) → unique_al(ay0) ⊦ a ∈ ax0, unique_al(ay)

User applied rule all left

And obtained the following new goals

Proof step 10:
perm(ax0, ay -1l (a × d)), a × d ∈ ay, perm(ay, (a × d)' + ax0), unique_al(ax0), perm(ay -1l (a × d), ax0), perm(ay -1l (a × d), ax0) ∧ perm(ax0, ay -1l (a × d)) → unique_al(ay -1l (a × d)) ⊦ a ∈ ax0, unique_al(ay)

Rule argument

pos: left 6 terms: ay -1l (a × d) abort: F discard: T computed: T

Additional information

Used terms: ay -1l (a × d)