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Proof step 2 from proof unique-02 (previous step)

a × d0 ∈ ax, a × d ∈ ax, unique_al(ax) ⊦ d = d0

User applied rule structural induction

And obtained the following new goals

Proof step 3:
∀ a, d0, d. a × d0 ∈ ax0 ∧ a × d ∈ ax0 ∧ unique_al(ax0) → d = d0 ⊦ a × d0 ∈ p + ax0 ∧ a × d ∈ p + ax0 ∧ unique_al(p + ax0) → d = d0

Rule argument

indvar: ax

Additional information

Used simplifier rules: assoclist freely generated by [], +;;% ⊦ ¬ p ∈ [];