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Proof step 3 from proof unique-del (previous step)

∀ a, d. unique_al(ax0 -1l (a × d)) → a ∈ ax0 -1l (a × d) ∨ unique_al(ax0) ⊦ unique_al((p + ax0) -1l (a × d)) → a ∈ (p + ax0) -1l (a × d) ∨ unique_al(p + ax0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ p + ax = p ' + ax;