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Proof step 5 from proof unique-del (previous step)

⊦ unique_al(((a × d)' + ax0) -1l (a0 × d0)) ∧ (∀ a, d. unique_al(ax0 -1l (a × d)) → a ∈ ax0 -1l (a × d) ∨ unique_al(ax0)) → a0 ∈ ((a × d)' + ax0) -1l (a0 × d0) ∨ unique_al((a × d)' + ax0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
unique_al(((a × d)' + ax0) -1l (a0 × d0)), ∀ a, d. unique_al(ax0 -1l (a × d)) → a ∈ ax0 -1l (a × d) ∨ unique_al(ax0) ⊦ unique_al((a × d)' + ax0), a0 ∈ ((a × d)' + ax0) -1l (a0 × d0)

Proof step 5 from proof unique-del (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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