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Proof step 2 from proof unique-put (previous step)

∀ a, d. unique_al(ax0[a, d]) ↔ unique_al(ax0) ⊦ unique_al((p + ax0)[a, d]) ↔ unique_al(p + ax0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ a, d. unique_al(ax0[a, d]) ↔ unique_al(ax0) ⊦ unique_al((p ' + ax0)[a, d]) ↔ unique_al(p ' + ax0)

Rule argument

Additional information

Used simplifier rules: ⊦ p + ax = p ' + ax;