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Proof step 14 from proof bitsinvert-size (previous step)

# sgn(bitsinvert(bits0)) = # sgn(bits0), bitsinvert(bits0) = boolvar0 ' + bits, (¬ boolvar0) ∈ bits0 ⊦ 1 + # bits0 = # sgn(bitsinvert(bits0).first ' + bits0), bits0 = [], boolvar0 ↔ ¬ bitsinvert(bits0).first

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

seq: bits ≠ [] ⊦ (boolvar ↔ bits.first) ∧ bits0 = bits.rest ↔ bits = boolvar + bits0 subst: [bits, boolvar, bits0] → [bitsinvert(bits0), boolvar, bits1] rotate: T spec: list-data inst: bitlista name: elim-list-c

Additional information

Used simplifier rules: inv-empty: ⊦ bitsinvert(bits) = [] ↔ bits = [];%bits ≠ [] ⊦ (boolvar ↔ bits.first) ∧ bits0 = bits.rest ↔ bits = boolvar + bits0; (elim) Used terms: bitsinvert(bits0), boolvar, bits1