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Proof step 25 from proof bitsinvert-size (previous step)

¬(bits0 ≠ [] ∧ (bits0.first ↔ boolvar)), bitsinvert(bits0) = (¬ boolvar)' + bits, # sgn(bitsinvert(bits0)) = # sgn(bits0), boolvar ∈ bits0 ⊦ bits0 = [], # sgn(bits0) = # sgn(boolvar ' + bits0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 26:
bitsinvert(bits0) = (¬ boolvar)' + bits, # sgn(bitsinvert(bits0)) = # sgn(bits0), boolvar ∈ bits0 ⊦ bits0 = [], # sgn(bits0) = # sgn(boolvar ' + bits0), bits0.first ↔ boolvar

Proof step 25 from proof bitsinvert-size (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information