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Proof step 28 from proof bitsinvert-size (previous step)

# sgn((¬ boolvar)' + bitsinvert(bits1)) = # sgn(boolvar0 ' + bits1), ¬ boolvar0 ↔ ¬ boolvar, boolvar ∈ bits1 ⊦ # sgn(boolvar0 ' + bits1) = # sgn(boolvar ' + boolvar0 ' + bits1), boolvar0 ↔ boolvar

User applied rule case distinction

And closed the goal!

Rule argument

pos: left 2

Additional information

Used simplifier rules: sgn-rec: ⊦ sgn(boolvar ' + boolvar ' + bits) = sgn(boolvar ' + bits);%sgn-rec: ⊦ sgn(boolvar ' + boolvar ' + bits) = sgn(boolvar ' + bits);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;