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Proof step 3 from proof bitsinvert-size (previous step)

bits0 = [] ∨ # sgn(bitsinvert(bits0)) = # sgn(bits0) ⊦ boolvar + bits0 = [], # sgn(bitsinvert(boolvar + bits0)) = # sgn(boolvar + bits0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: inv-append: ⊦ bitsinvert(bits + bits0) = bitsinvert(bits) + bitsinvert(bits0);%inv-one: ⊦ bitsinvert(boolvar ') = (¬ boolvar)';%invert-base: ⊦ bitsinvert([]) = [];%sgn-one: ⊦ sgn(boolvar ') = boolvar ';% ⊦ # boolvar ' = 0 +1;% ⊦ bits + [] = bits;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;