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Proof step 6 from proof bitsinvert-size (previous step)

¬(bitsinvert(bits0) ≠ [] ∧ (bitsinvert(bits0).first ↔ ¬ boolvar)), # sgn(bitsinvert(bits0)) = # sgn(bits0) ⊦ # sgn((¬ boolvar)' + bitsinvert(bits0)) = # sgn(boolvar ' + bits0), bits0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
# sgn(bitsinvert(bits0)) = # sgn(bits0) ⊦ # sgn((¬ boolvar)' + bitsinvert(bits0)) = # sgn(boolvar ' + bits0), bits0 = [], bitsinvert(bits0).first ↔ ¬ boolvar

Rule argument

Additional information

Used simplifier rules: inv-empty: ⊦ bitsinvert(bits) = [] ↔ bits = [];