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Proof step 2 from proof fill-empty (previous step)

fillsgn(n, bits) = [] ⊦ bits = [] ∧ n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ n ≤ # bits → fillsgn(n, bits) = bits
Proof step 4:
¬ n ≤ # bits, fillsgn(n, bits) = [] ⊦ bits = [] ∧ n = 0

Rule argument

name: fillsgn-longer rotate: F subst: [bits, n] → [bits, n]

Additional information

Used simplifier rules: ⊦ # [] = 0;% ⊦ m ≤ 0 ↔ m = 0; Used terms: bits, n