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Proof step 5 from proof fill-fill (previous step)

bits = boolvar + bits0 ⊦ bits = [], fillsgn(n0 + # bits, bits) = mklist(boolvar, n0) + bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ fillsgn((1 + # bits0) + n0, boolvar ' + bits0) = (boolvar ' + mklist(boolvar, n0)) + bits0

Rule argument

Additional information

Used simplifier rules: ⊦ mklist(boolvar, n) + boolvar ' = boolvar ' + mklist(boolvar, n);% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;