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Proof step 8 from proof fill-last (previous step)

1 ≤ #(bits + boolvar ') ⊦ bits = [], bits + boolvar ' = fillsgn(0, bits) + boolvar '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ bits = [], bits = fillsgn(0, bits)

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m ≤ m + n;% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + bits0 = bits1 + bits0 ↔ bits = bits1;