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Proof step 10 from proof fill-lastn-03 (previous step)

# bits ≤ n ∧ bits ≠ [], m < n, # bits < n, m < # bits, m + 1 < n ⊦ bits = [], lastn(m, mklist(bits.first, n - # bits) + bits) = lastn(m, bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
m < n, # bits < n, m < # bits, m + 1 < n ⊦ lastn(m, mklist(bits.first, n - # bits) + bits) = lastn(m, bits), bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → m ≤ n;