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Proof step 31 from proof fill-lastn-03 (previous step)

¬ n - m ≤ # mklist(bits.first, n - # bits), # bits ≤ n, # bits ≤ m, m ≤ n ⊦ bits = [], restn(n - m, mklist(bits.first, n - # bits) + bits) = mklist(bits.first, m - # bits) + bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
(n - # bits) + m < n, m ≤ n, # bits ≤ m, # bits ≤ n ⊦ restn(n - m, mklist(bits.first, n - # bits) + bits) = mklist(bits.first, m - # bits) + bits, bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0;% ⊦ m < n → n ≠ 0; (forward)%n0 ≤ n ⊦ n - n0 ≤ m ↔ n ≤ m + n0;% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m ≤ n → (n < m ↔ false);% ⊦ # mklist(boolvar, n) = n;