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Proof step 33 from proof fill-lastn-03 (previous step)

n - m ≤ # mklist(bits.first, n - # bits), # bits ≤ n, # bits ≤ m, m ≤ n ⊦ bits = [], restn(n - m, mklist(bits.first, n - # bits)) + bits = mklist(bits.first, m - # bits) + bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 34:
# bits ≤ (n - # bits) + m, n ≤ (n - # bits) + m, m ≤ n, # bits ≤ m, # bits ≤ n ⊦ restn(n - m, mklist(bits.first, n - # bits)) = mklist(bits.first, m - # bits), bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m ≤ m + n;% ⊦ n ≤ n0 ∧ n0 ≤ n1 → n ≤ n1; (forward)%n0 ≤ n ⊦ n - n0 ≤ m ↔ n ≤ m + n0;% ⊦ # mklist(boolvar, n) = n;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + bits0 = bits1 + bits0 ↔ bits = bits1;