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Proof step 5 from proof fill-lastn-03 (previous step)

m < # bits, m ≤ n ⊦ lastn(m, fillsgn(n, bits)) = lastn(m, bits), bits = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ n ≤ # bits → fillsgn(n, bits) = bits
Proof step 7:
¬ n ≤ # bits, m < # bits, m ≤ n ⊦ lastn(m, fillsgn(n, bits)) = lastn(m, bits), bits = []

Rule argument

name: fillsgn-longer rotate: F subst: [bits, n] → [bits, n]

Additional information

Used terms: bits, n