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Proof step 5 from proof fill-lastn-05 (previous step)

# bits0 ≤ m ⊦ bits0 = [], lastn(m, fillsgn(m, bits0)) = fillsgn(m, bits0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ n = # bits → lastn(n, bits) = bits

Rule argument

seq: ⊦ n = # bits → lastn(n, bits) = bits subst: [bits, n] → [fillsgn(m, bits0), m] rotate: F spec: list-del inst: bitlista name: lastN-all

Additional information

Used simplifier rules: fill-length: ⊦ # bits ≤ n → # fillsgn(n, bits) = n; Used terms: fillsgn(m, bits0), m