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Proof step 1 from proof fill-nls (conclusion)

⊦ ¬ # fillsgn(n, bits) < # bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# fillsgn(n, bits) < # bits ⊦ bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ # bits = 0 ↔ bits = [];% ⊦ m < n → n ≠ 0; (forward)