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Proof step 1 from proof fill-one (conclusion)

⊦ fillsgn(1, boolvar ') = boolvar '

User applied rule insert lemma

And obtained the following new goals

Proof step 2:
⊦ n ≤ # bits → fillsgn(n, bits) = bits

Rule argument

name: fillsgn-longer subst: [n, bits] → [1, boolvar ']

Additional information

Used simplifier rules: ⊦ # boolvar ' = 0 +1; Used terms: 1, boolvar '