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Proof step 5 from proof fill-rec-one (previous step)

fillsgn(n, boolvar ') = mklist(boolvar, n - 0) ⊦ mklist(boolvar, n - 0) = mklist(boolvar, n), n = 0

Heuristic elimination applied rule insert elim lemma

And closed the goal!

Rule argument

seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [n, 0, n0] rotate: T spec: nat inst: name: elim-sub

Additional information

Used simplifier rules: ⊦ 0 ≤ m;% ⊦ 0 + m = m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = n + m;%n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n, 0, n0