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Proof step 1 from proof fill-rec (conclusion)

⊦ bits ≠ [] ∧ # bits < n → fillsgn(n, bits) = bits.first ' + fillsgn(n -1, bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# bits < n ⊦ fillsgn(n, bits) = bits.first ' + fillsgn(n - 1, bits), bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0;% ⊦ m < n → n ≠ 0; (forward)% ⊦ n -1 = n - 1;