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Proof step 7 from proof fill-sgn-02 (previous step)

fillsgn(# bits0, sgn(bits0)) = bits0 ⊦ fillsgn(1 + # bits0, sgn(boolvar ' + bits0)) = boolvar ' + bits0, bits0 = [], bits0.first ↔ boolvar

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

seq: bits ≠ [] ⊦ (boolvar ↔ bits.first) ∧ bits0 = bits.rest ↔ bits = boolvar + bits0 subst: [bits, boolvar, bits0] → [bits0, boolvar0, bits] rotate: T spec: list-data inst: bitlista name: elim-list-c

Additional information

Used simplifier rules: bits ≠ [] ⊦ (boolvar ↔ bits.first) ∧ bits0 = bits.rest ↔ bits = boolvar + bits0; (elim) Used terms: bits0, boolvar0, bits